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8y^2+86y-22=0
a = 8; b = 86; c = -22;
Δ = b2-4ac
Δ = 862-4·8·(-22)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-90}{2*8}=\frac{-176}{16} =-11 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+90}{2*8}=\frac{4}{16} =1/4 $
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